Your friend is in university and there is a coding challenge going on. A string S of lowercase letters is displayed over the screen. The length of the string is N. An integer M is also displayed over the screen.Your task is write a program to determine if we can make the string Palindrome by performing at most M operations on the provided string
Question
Your friend is in university and there is a coding challenge going on. A string S of lowercase letters is displayed over the screen. The length of the string is N. An integer M is also displayed over the screen.Your task is write a program to determine if we can make the string Palindrome by performing at most M operations on the provided string
Solution
Sure, let's break down the problem step by step and write a program to determine if we can make the string a palindrome by performing at most M operations.
-
Understand the Problem: We need to check if we can convert a given string
Sinto a palindrome by changing at mostMcharacters. -
Palindrome Definition: A string is a palindrome if it reads the same backward as forward.
-
Approach:
- Compare characters from the beginning and the end of the string moving towards the center.
- Count the number of mismatched character pairs.
- If the number of mismatches is less than or equal to
M, then it is possible to make the string a palindrome with at mostMoperations.
-
Steps:
- Initialize a counter for mismatches.
- Use a loop to compare characters from the start and end of the string.
- Increment the mismatch counter whenever characters do not match.
- After the loop, check if the mismatch counter is less than or equal to
M.
Here is the program:
def can_be_palindrome(S, N, M):
# Initialize mismatch counter
mismatch_count = 0
# Compare characters from start and end
for i in range(N // 2):
if S[i] != S[N - i - 1]:
mismatch_count += 1
# Check if mismatches are within the allowed operations
if mismatch_count <= M:
return True
else:
return False
# Example usage
S = "abca"
N = len(S)
M = 1
print(can_be_palindrome(S, N, M)) # Output: True
Explanation:
- The function
can_be_palindrometakes the stringS, its lengthN, and the maximum allowed operationsMas input. - It initializes a counter
mismatch_countto zero. - It then iterates from the start to the middle of the string, comparing characters from the start and end.
- If characters do not match, it increments the
mismatch_count. - Finally, it checks if the
mismatch_countis less than or equal toMand returnsTrueif it is, otherwiseFalse.
In the example provided, the string "abca" can be made a palindrome by changing one character ('c' to 'b'), so the function returns True.
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class Solution { public boolean isPalindrome(int x) { String num =Integer.toString(x); for(int i=num.length()-1;i<0;i--){ String a =" "+num; if(num==a){ System.out.println("it is palindrome:"+a); }else{ System.out.println("it is not palindrome:"+a); } } }}
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