Knowee
Questions
Features
Study Tools

Your friend is in university and there is a coding challenge going on. A string S of lowercase letters is displayed over the screen. The length of the string is N. An integer M is also displayed over the screen.Your task is write a program to determine if we can make the string Palindrome by performing at most M operations on the provided string

Question

Your friend is in university and there is a coding challenge going on. A string S of lowercase letters is displayed over the screen. The length of the string is N. An integer M is also displayed over the screen.Your task is write a program to determine if we can make the string Palindrome by performing at most M operations on the provided string

🧐 Not the exact question you are looking for?Go ask a question

Solution

Sure, let's break down the problem step by step and write a program to determine if we can make the string a palindrome by performing at most M operations.

  1. Understand the Problem: We need to check if we can convert a given string S into a palindrome by changing at most M characters.

  2. Palindrome Definition: A string is a palindrome if it reads the same backward as forward.

  3. Approach:

    • Compare characters from the beginning and the end of the string moving towards the center.
    • Count the number of mismatched character pairs.
    • If the number of mismatches is less than or equal to M, then it is possible to make the string a palindrome with at most M operations.
  4. Steps:

    • Initialize a counter for mismatches.
    • Use a loop to compare characters from the start and end of the string.
    • Increment the mismatch counter whenever characters do not match.
    • After the loop, check if the mismatch counter is less than or equal to M.

Here is the program:

def can_be_palindrome(S, N, M):
    # Initialize mismatch counter
    mismatch_count = 0
    
    # Compare characters from start and end
    for i in range(N // 2):
        if S[i] != S[N - i - 1]:
            mismatch_count += 1
    
    # Check if mismatches are within the allowed operations
    if mismatch_count <= M:
        return True
    else:
        return False

# Example usage
S = "abca"
N = len(S)
M = 1
print(can_be_palindrome(S, N, M))  # Output: True

Explanation:

  • The function can_be_palindrome takes the string S, its length N, and the maximum allowed operations M as input.
  • It initializes a counter mismatch_count to zero.
  • It then iterates from the start to the middle of the string, comparing characters from the start and end.
  • If characters do not match, it increments the mismatch_count.
  • Finally, it checks if the mismatch_count is less than or equal to M and returns True if it is, otherwise False.

In the example provided, the string "abca" can be made a palindrome by changing one character ('c' to 'b'), so the function returns True.

This problem has been solved

Similar Questions

Write a Java program to print the smallest and biggest possible palindrome word in a given string. If no palindrome is found in the given string, then, print 'no palindrome'.Input FormatIn the first line read a stringOutput FormatThe first line contains the smallest palindrome word  (or) no palindromeThe nextline contains the biggest palindrome word

Write a python program to check the given string is palindrome or not.

A positive integer is called a palindrome if its representation in the decimal system is the same when read from left to right and from right to left. For a given positive integer K of not more than 1000000 digits, write the value of the smallest palindrome larger than K to output. Numbers are always displayed without leading zeros.InputThe first line contains integer t, the number of test cases. Followed by t lines containing integers K.OutputFor each K, output the smallest palindrome larger than K.ExampleInput:28082133Output:8182222Warning: large Input/Output data, be careful with certain languages

Write a programme to check whether given input is palindrome or notConstraintsABC != PalindromeMAM == Palindrome123 != Palindrome151 == Palindrome

class Solution { public boolean isPalindrome(int x) { String num =Integer.toString(x); for(int i=num.length()-1;i<0;i--){ String a =" "+num; if(num==a){ System.out.println("it is palindrome:"+a); }else{ System.out.println("it is not palindrome:"+a); } } }}

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.