Sure, here is a Python solution for your problem:

def find_palindromes_in_sub_string(input_string, j, k): count = 0 while j >= 0 and k < len(input_string): if input_string[j] != input_string[k]: break if k - j + 1 > 1: count += 1 j -= 1 k += 1 return count def palindrome_sub_strings(input_string): count = 0 for i in range(len(input_string)): # find odd length palindromes count += find_palindromes_in_sub_string(input_string, i - 1, i + 1) # find even length palindromes count += find_palindromes_in_sub_string(input_string, i - 1, i) return count input_string = "abcba" print("Total palindrome substrings: ", palindrome_sub_strings(input_string))

Here is a step-by-step explanation of the code:

We define a helper function find_palindromes_in_sub_string(input_string, j, k) that finds all palindromes in the substring of input_string that starts at index j and ends at index k. It returns the count of such palindromes.

In the main function palindrome_sub_strings(input_string), we iterate over each character in the input string.

For each character, we call find_palindromes_in_sub_string(input_string, i - 1, i + 1) to find all odd length palindromes that have the current character at the center.

We also call find_palindromes_in_sub_string(input_string, i - 1, i) to find all even length palindromes that have the current character at the center.

We add up the counts from steps 3 and 4 to get the total count of palindrome substrings.

Finally, we print the total count of palindrome substrings.

Question

Sure, here is a Python solution for your problem:

```python
def find_palindromes_in_sub_string(input_string, j, k):
    count = 0
    while j >= 0 and k < len(input_string):
        if input_string[j] != input_string[k]:
            break
        if k - j + 1 > 1:
            count += 1
        j -= 1
        k += 1
    return count

def palindrome_sub_strings(input_string):
    count = 0
    for i in range(len(input_string)):
        # find odd length palindromes
        count += find_palindromes_in_sub_string(input_string, i - 1, i + 1)
        # find even length palindromes
        count += find_palindromes_in_sub_string(input_string, i - 1, i)
    return count

input_string = "abcba"
print("Total palindrome substrings: ", palindrome_sub_strings(input_string))
```

Here is a step-by-step explanation of the code:

1. We define a helper function `find_palindromes_in_sub_string(input_string, j, k)` that finds all palindromes in the substring of `input_string` that starts at index `j` and ends at index `k`. It returns the count of such palindromes.

2. In the main function `palindrome_sub_strings(input_string)`, we iterate over each character in the input string.

3. For each character, we call `find_palindromes_in_sub_string(input_string, i - 1, i + 1)` to find all odd length palindromes that have the current character at the center.

4. We also call `find_palindromes_in_sub_string(input_string, i - 1, i)` to find all even length palindromes that have the current character at the center.

5. We add up the counts from steps 3 and 4 to get the total count of palindrome substrings.

6. Finally, we print the total count of palindrome substrings.

Knowee AI · Accepted Answer

Sure, here is a Python solution for your problem:

```python
def find_palindromes_in_sub_string(input_string, j, k):
    count = 0
    while j >= 0 and k < len(input_string):
        if input_string[j] != input_string[k]:
            break
        if k - j + 1 > 1:
            count += 1
        j -= 1
        k += 1
    return count

def palindrome_sub_strings(input_string):
    count = 0
    for i in range(len(input_string)):
        # find odd length palindromes
        count += find_palindromes_in_sub_string(input_string, i - 1, i + 1)
        # find even length palindromes
        count += find_palindromes_in_sub_string(input_string, i - 1, i)
    return count

input_string = "abcba"
print("Total palindrome substrings: ", palindrome_sub_strings(input_string))
```

Here is a step-by-step explanation of the code:

1. We define a helper function `find_palindromes_in_sub_string(input_string, j, k)` that finds all palindromes in the substring of `input_string` that starts at index `j` and ends at index `k`. It returns the count of such palindromes.

2. In the main function `palindrome_sub_strings(input_string)`, we iterate over each character in the input string.

3. For each character, we call `find_palindromes_in_sub_string(input_string, i - 1, i + 1)` to find all odd length palindromes that have the current character at the center.

4. We also call `find_palindromes_in_sub_string(input_string, i - 1, i)` to find all even length palindromes that have the current character at the center.

5. We add up the counts from steps 3 and 4 to get the total count of palindrome substrings.

6. Finally, we print the total count of palindrome substrings.

Given a string, discover all non-single letter palindrome substrings.

Question

Solution

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