If O2 gas is bubbled through water at 303 K, the number of millimoles of O2 gas that dissolve in 1 litre of water is ________________. (Nearest integer)(Given: Henry’s Law constant for O2 at 303 K is 46.82 k bar and partial pressure of O2 = 0.920 bar)(Assume solubility of O2 in water is too small, nearly negligible)
Question
If O2 gas is bubbled through water at 303 K, the number of millimoles of O2 gas that dissolve in 1 litre of water is ________________. (Nearest integer)(Given: Henry’s Law constant for O2 at 303 K is 46.82 k bar and partial pressure of O2 = 0.920 bar)(Assume solubility of O2 in water is too small, nearly negligible)
Solution
To solve this problem, we need to use Henry's Law, which states that the amount of dissolved gas is proportional to its partial pressure in the gas phase. The formula for Henry's Law is:
C = P/kH
where: C is the concentration of the dissolved gas, P is the partial pressure of the gas, and kH is the Henry's Law constant.
Given in the problem: P = 0.920 bar kH = 46.82 k bar
We can substitute these values into the formula:
C = 0.920 bar / 46.82 k bar
To convert k bar to bar, we multiply by 1000:
C = 0.920 bar / (46.82 * 1000) bar
C = 0.0000197 mol/L
To convert from mol/L to mmol/L, we multiply by 1000:
C = 0.0000197 * 1000 mmol/L
C = 0.0197 mmol/L
Rounding to the nearest integer, the number of millimoles of O2 gas that dissolve in 1 litre of water is approximately 0.
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