What will be the output of the following Python code?i = 1while True:    if i%3 == 0:        continue    print(i)    i+ =1

The provided Python code will result in an infinite loop. This is because the continue statement is used when the condition i%3 == 0 is met. The continue statement skips the rest of the code inside the enclosing loop for the current iteration and moves the control back to the top of the loop.

However, the increment operation i += 1 is after the continue statement, so when i is a multiple of 3, the increment operation is skipped, and i remains the same. This causes the loop to run indefinitely.

Also, there is a syntax error in your code. The correct increment operation should be i += 1, not i+ =1.

Here is the corrected code:

i = 1
while True: 
    if i%3 == 0: 
        i += 1
        continue 
    print(i) 
    i += 1

This code will print all numbers that are not multiples of 3.