Study the following program:i = 0while i < 3: print(i) i += 1 else: print(0)
Question
Study the following program:i = 0while i < 3: print(i) i += 1 else: print(0)
Solution
This is a simple Python program that uses a while loop to print numbers. Here's a step-by-step explanation:
-
The variable
iis initialized with the value0. -
The
whileloop checks if the value ofiis less than3. If it is, it enters the loop. -
Inside the loop, it first prints the current value of
i. -
Then, it increments the value of
iby1using the+=operator. -
The loop then goes back to step 2, checking the condition again. If
iis still less than3, it repeats steps 3 and 4. -
This continues until
iis no longer less than3(i.e., wheniis3), at which point it exits the loop. -
After the loop, the
elseclause is executed, which prints0.
So, the output of this program would be:
0
1
2
0
Similar Questions
What will be the output for the following code?i=0while(i<3): j=0 while(j<3): print(i,j,end=" ") j+=1 print()
Will the following code ever end?i = 0while i > 0: print(i) i = i + 1
What will be the output of the following Python program? i = 0while i < 5: print(i) i += 1 if i == 3: breakelse: print(0)
What will be the output of the following Python code?i = 1while True: if i%3 == 0: continue print(i) i+ =1
1 pointWhat is the output of the following code?i = 2while True: if i%3 == 0: break print(i) i += 22 4 6 8 10 ...2 32 4Error
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.