What will be the output of the following Python code?i = 7while True: if i%0O11 == 0: break print(i) i += 2
Question
What will be the output of the following Python code?i = 7while True: if i%0O11 == 0: break print(i) i += 2
Solution
The output of the given Python code will be:
7 9
Here's the step-by-step explanation:
-
The variable
iis initialized with the value 7. -
The
while True:loop starts, which will run indefinitely until abreakstatement is encountered. -
Inside the loop, the
ifcondition checks whether the remainder ofidivided by0O11(which is octal for 9) is 0. If it is, the loop willbreak. -
If the
ifcondition is not met, the program will print the current value ofiand then incrementiby 2. -
The loop then repeats from step 3 with the new value of
i. -
The values 7 and 9 are printed because they are not divisible by 9. When
ibecomes 11, theifcondition is met (since 11 is divisible by 9 with no remainder), so the loop breaks and the program ends.
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