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What will be the output of the following Python code?i = 7while True:    if i%0O11 == 0:        break     print(i)     i += 2

Question

What will be the output of the following Python code?i = 7while True:    if i%0O11 == 0:        break     print(i)     i += 2

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Solution

The output of the given Python code will be:

7 9

Here's the step-by-step explanation:

  1. The variable i is initialized with the value 7.

  2. The while True: loop starts, which will run indefinitely until a break statement is encountered.

  3. Inside the loop, the if condition checks whether the remainder of i divided by 0O11 (which is octal for 9) is 0. If it is, the loop will break.

  4. If the if condition is not met, the program will print the current value of i and then increment i by 2.

  5. The loop then repeats from step 3 with the new value of i.

  6. The values 7 and 9 are printed because they are not divisible by 9. When i becomes 11, the if condition is met (since 11 is divisible by 9 with no remainder), so the loop breaks and the program ends.

This problem has been solved

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