What will be the output of the following Python code?i = 1while True: if i%3 == 0: break print(i) i + = 1
Question
What will be the output of the following Python code?i = 1while True: if i%3 == 0: break print(i) i + = 1
Solution
The given Python code will result in a syntax error. The reason is the space between the '+' and '=' in the line 'i + = 1'. Python doesn't allow spaces in its increment operator. The correct syntax should be 'i += 1'.
If we correct this error, the code will run as follows:
i = 1
while True:
if i%3 == 0:
break
print(i)
i += 1
This code initializes a variable 'i' to 1. Then it enters an infinite loop (because the condition for the while loop is just 'True'). In this loop, it first checks if 'i' is divisible by 3. If it is, it breaks out of the loop. If it isn't, it prints the value of 'i' and then increments 'i' by 1.
So, the output of this corrected code will be:
1
2
It prints 1 and 2, then when 'i' becomes 3, the condition 'i%3 == 0' becomes True and it breaks the loop, so 3 is not printed.
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