What is the output of the following program?t = 1while True:  if t%2 == 0:    break  print(t)  t + = 1Options121No Output

The output of the program will be 1.

Here's the step by step explanation:

1. The variable t is initialized with the value 1.
2. The while True: loop starts, which will run indefinitely until a break statement is encountered.
3. Inside the loop, the if statement checks if t is even (t%2 == 0). If it is, the break statement will be executed and the loop will end. However, since t is currently 1 (which is not even), the break statement is not executed.
4. The print(t) statement is then executed, printing the current value of t, which is 1.
5. The t += 1 statement increments t by 1. Now t is 2.
6. The loop starts again from the beginning. This time, t is 2, so the if statement is true and the break statement is executed. The loop ends here.
7. Since there are no more statements after the loop, the program ends.

So, the only output produced by this program is 1.