The amount of water dispensed by a water dispenser is normally distributed, with a mean of 12.10 ounces and a standard deviation of 0.25 ounces. In which range will the amount of water dispensed be found 68% of the time?A.11.60 ounces to 12.60 ouncesB.11.85 ounces to 12.35 ouncesC.11.10 ounces to 13.10 ouncesD.11.35 ounces to 12.85 ouncesSUBMITarrow_backPREVIOUS

The annual per capita consumption of bottled water was 34.8 gallons.Assume that the per capita consumption of bottled water is approximately normally distributed with a mean of 34.8 and a standard deviation of 12 gallons. a.What is the probability that someone consumed more than 35 gallons of bottled water? b.What is the probability that someone consumed between 20 and 30 gallons of bottled water? c.What is the probability that someone consumed less than 20 gallons of bottled water? d.90%of people consumed less than how many gallons of bottled water?Round to four decimal places as​ needed.)

The volume of beverage in a 12-ounces can is normally distributed with mean 12.07 ounces and standard deviation 0.03 ounces.(a) What is the probability that a randomly selected can will contain more than 12.09 ounces?(b) What is the probability that a randomly selected can will contain between 12 and 12.05 ounces?(c) Is it unusual for a can to be under filled (contain less than 12 ounces)?

Use the Empirical Rule to answer each question.During 1 week an overnight delivery company found that the weights of its parcels were normally distributed, with a mean of 28 ounces and a standard deviation of 7 ounces.(a) What percent of the parcels weighed between 14 ounces and 35 ounces? (Round your answer to one decimal place.) %(b) What percent of the parcels weighed more than 49 ounces? (Round your answer to two decimal places.) %

Faculty in the psychology department at State University consume an average of 5 cups of coffee per day with a standard deviation of 1.5. The distribution is normal. What proportion of faculty consumes an amount between 4 and 6 cups?Choose one0.54680.49720.50none of these

ough the packages are labeled as 8 ounces,the company wants the packages to contain a mean of 8.17 ounces so that virtually none of the packages contain less than 8 ounces.A sample of 50 packages is selected periodically,and the packaging process is stopped if there is evidence that the mean amount packaged is different from 8.17 ounces.Suppose that in a particular sample of 50 packages,the mean amount dispensed is 8.168 ounces,with a sample standard deviation of 0.059 ounce.Complete parts(a)and(b). Click here to view page 1 of the critical values for the t Distribution. Click here to view page 2 of the critical values for the t Distribution. 0· a.Is there evidence that the population mean amount is different from 8.17 ounces?(Use a 0.01 level of significance.) State the null and alternative hypotheses. H0:μ=8.17 H1μ≠8.17 (Type integers or decimals.) Identify the critical value(s). The critical value(s)is(are) (Round to four decimal places as needed.Use a comma to separate answers as needed.) ChatGPT To test whether there is evidence that the population mean amount is different from 8.17 ounces at a 0.01 level of significance, you can set up the null and alternative hypotheses as follows: Null Hypothesis (H0): The population mean amount of candies is equal to 8.17 ounces. H0: μ = 8.17 Alternative Hypothesis (H1): The population mean amount of candies is different from 8.17 ounces. H1: μ ≠ 8.17 To identify the critical value(s) for a two-tailed test at a 0.01 level of significance, you can use a t-distribution table or a calculator. Since the sample size is 50, you have 49 degrees of freedom (df = n - 1). Using a t-distribution table with 49 degrees of freedom and a significance level of 0.01 (two-tailed), you can find the critical values. Typically, for a two-tailed test at 0.01 significance level, the critical values are approximately ±2.6851 (rounded to four decimal places). So, the critical value(s) for this test are approximately ±2.6851. If the calculated t-statistic falls beyond these critical values in either the lower or upper tail, you would reject the null hypothesis.