Use the Empirical Rule to answer each question.During 1 week an overnight delivery company found that the weights of its parcels were normally distributed, with a mean of 28 ounces and a standard deviation of 7 ounces.(a) What percent of the parcels weighed between 14 ounces and 35 ounces? (Round your answer to one decimal place.) %(b) What percent of the parcels weighed more than 49 ounces? (Round your answer to two decimal places.) %
Question
Use the Empirical Rule to answer each question.During 1 week an overnight delivery company found that the weights of its parcels were normally distributed, with a mean of 28 ounces and a standard deviation of 7 ounces.(a) What percent of the parcels weighed between 14 ounces and 35 ounces? (Round your answer to one decimal place.) %(b) What percent of the parcels weighed more than 49 ounces? (Round your answer to two decimal places.) %
Solution
(a) The Empirical Rule states that for a normal distribution, approximately 68% of the data falls within one standard deviation of the mean, 95% falls within two standard deviations, and 99.7% falls within three standard deviations.
In this case, the mean is 28 ounces and the standard deviation is 7 ounces.
To find the percentage of parcels that weighed between 14 ounces and 35 ounces, we need to calculate how many standard deviations away 14 and 35 ounces are from the mean.
14 ounces is two standard deviations below the mean (28 - 14 = 14, 14/7 = 2) and 35 ounces is one standard deviation above the mean (35 - 28 = 7, 7/7 = 1).
According to the Empirical Rule, approximately 95% of the data falls within two standard deviations of the mean and 68% falls within one standard deviation. Therefore, the percentage of parcels that weighed between 14 ounces and 35 ounces is the difference between these two percentages, which is 95% - 68% = 27%.
So, approximately 27.0% of the parcels weighed between 14 ounces and 35 ounces.
(b) To find the percentage of parcels that weighed more than 49 ounces, we need to calculate how many standard deviations away 49 ounces is from the mean.
49 ounces is three standard deviations above the mean (49 - 28 = 21, 21/7 = 3).
According to the Empirical Rule, approximately 99.7% of the data falls within three standard deviations of the mean. Therefore, the percentage of parcels that weighed more than 49 ounces is the difference between 100% and 99.7%, which is 0.3%.
So, approximately 0.30% of the parcels weighed more than 49 ounces.
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