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ough the packages are labeled as 8 ounces,the company wants the packages to contain a mean of 8.17 ounces so that virtually none of the packages contain less than 8 ounces.A sample of 50 packages is selected periodically,and the packaging process is stopped if there is evidence that the mean amount packaged is different from 8.17 ounces.Suppose that in a particular sample of 50 packages,the mean amount dispensed is 8.168 ounces,with a sample standard deviation of 0.059 ounce.Complete parts(a)and(b). Click here to view page 1 of the critical values for the t Distribution. Click here to view page 2 of the critical values for the t Distribution. 0· a.Is there evidence that the population mean amount is different from 8.17 ounces?(Use a 0.01 level of significance.) State the null and alternative hypotheses. H0:μ=8.17 H1μ≠8.17 (Type integers or decimals.) Identify the critical value(s). The critical value(s)is(are) (Round to four decimal places as needed.Use a comma to separate answers as needed.) ChatGPT To test whether there is evidence that the population mean amount is different from 8.17 ounces at a 0.01 level of significance, you can set up the null and alternative hypotheses as follows: Null Hypothesis (H0): The population mean amount of candies is equal to 8.17 ounces. H0: μ = 8.17 Alternative Hypothesis (H1): The population mean amount of candies is different from 8.17 ounces. H1: μ ≠ 8.17 To identify the critical value(s) for a two-tailed test at a 0.01 level of significance, you can use a t-distribution table or a calculator. Since the sample size is 50, you have 49 degrees of freedom (df = n - 1). Using a t-distribution table with 49 degrees of freedom and a significance level of 0.01 (two-tailed), you can find the critical values. Typically, for a two-tailed test at 0.01 significance level, the critical values are approximately ±2.6851 (rounded to four decimal places). So, the critical value(s) for this test are approximately ±2.6851. If the calculated t-statistic falls beyond these critical values in either the lower or upper tail, you would reject the null hypothesis.

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ough the packages are labeled as 8 ounces,the company wants the packages to contain a mean of 8.17 ounces so that virtually none of the packages contain less than 8 ounces.A sample of 50 packages is selected periodically,and the packaging process is stopped if there is evidence that the mean amount packaged is different from 8.17 ounces.Suppose that in a particular sample of 50 packages,the mean amount dispensed is 8.168 ounces,with a sample standard deviation of 0.059 ounce.Complete parts(a)and(b). Click here to view page 1 of the critical values for the t Distribution. Click here to view page 2 of the critical values for the t Distribution. 0· a.Is there evidence that the population mean amount is different from 8.17 ounces?(Use a 0.01 level of significance.) State the null and alternative hypotheses. H0:μ=8.17 H1μ≠8.17 (Type integers or decimals.) Identify the critical value(s). The critical value(s)is(are) (Round to four decimal places as needed.Use a comma to separate answers as needed.)

ChatGPT To test whether there is evidence that the population mean amount is different from 8.17 ounces at a 0.01 level of significance, you can set up the null and alternative hypotheses as follows:

Null Hypothesis (H0): The population mean amount of candies is equal to 8.17 ounces. H0: μ = 8.17

Alternative Hypothesis (H1): The population mean amount of candies is different from 8.17 ounces. H1: μ ≠ 8.17

To identify the critical value(s) for a two-tailed test at a 0.01 level of significance, you can use a t-distribution table or a calculator. Since the sample size is 50, you have 49 degrees of freedom (df = n - 1).

Using a t-distribution table with 49 degrees of freedom and a significance level of 0.01 (two-tailed), you can find the critical values. Typically, for a two-tailed test at 0.01 significance level, the critical values are approximately ±2.6851 (rounded to four decimal places).

So, the critical value(s) for this test are approximately ±2.6851. If the calculated t-statistic falls beyond these critical values in either the lower or upper tail, you would reject the null hypothesis.

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