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A manufacturer of chocolate candies uses machines to package candies as they move along a filling line.Although the packages are labeled as 8 ounces,the company wants the packages to contain a mean of 8.17 ounces so that virtually none of the packages contain less than 8 ounces.A sample of 50 packages is selected periodically,and the packaging process is stopped if there is deviation of 0.059 ounce.Complete parts (a)and(b) State the null and alternative hypotheses. H0μ= 8.17 H1:μ≠8.17 Determine the test statistic. The test statistic is

Question

A manufacturer of chocolate candies uses machines to package candies as they move along a filling line.Although the packages are labeled as 8 ounces,the company wants the packages to contain a mean of 8.17 ounces so that virtually none of the packages contain less than 8 ounces.A sample of 50 packages is selected periodically,and the packaging process is stopped if there is deviation of 0.059 ounce.Complete parts (a)and(b) State the null and alternative hypotheses. H0μ= 8.17 H1:μ≠8.17 Determine the test statistic. The test statistic is

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Solution

To answer this question, we first need to understand the null and alternative hypotheses.

The null hypothesis (H0) is a statement of no effect or no difference. In this case, the null hypothesis is that the mean weight of the chocolate candies is 8.17 ounces. So, H0: μ = 8.17.

The alternative hypothesis (H1) is a statement that contradicts the null hypothesis. Here, the alternative hypothesis is that the mean weight of the chocolate candies is not 8.17 ounces. So, H1: μ ≠ 8.17.

To determine the test statistic, we need more information such as the standard deviation of the sample and the actual mean weight of the candies in the sample. The test statistic is usually calculated as the difference between the sample mean and the hypothesized mean, divided by the standard error of the sample mean.

However, without the standard deviation or the actual mean weight of the candies in the sample, we cannot calculate the test statistic.

This problem has been solved

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