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The store manager has to prepare 15.00 litres of 0.0500 M hydrochloric acid. She has accurately prepared a 5.00 M solution of the acid which she wishes to dilute. What volume of the 5.00 M acid should she measure out to dilute to 15.00 litres?

Question

The store manager has to prepare 15.00 litres of 0.0500 M hydrochloric acid. She has accurately prepared a 5.00 M solution of the acid which she wishes to dilute. What volume of the 5.00 M acid should she measure out to dilute to 15.00 litres?

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Solution

To solve this problem, we can use the formula M1V1 = M2V2, where M1 is the molarity of the concentrated solution, V1 is the volume of the concentrated solution needed, M2 is the molarity of the diluted solution, and V2 is the volume of the diluted solution.

Here, M1 = 5.00 M, M2 = 0.0500 M, and V2 = 15.00 L. We need to find V1.

Substituting the given values into the formula, we get:

5.00 M * V1 = 0.0500 M * 15.00 L

Solving for V1, we get:

V1 = (0.0500 M * 15.00 L) / 5.00 M = 0.150 L or 150 mL

So, the store manager should measure out 150 mL of the 5.00 M hydrochloric acid solution to dilute to 15.00 litres.

This problem has been solved

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