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Maria needs to dilute her stock of 15.0 M HNO3 solution for an experiment. She wants to prepare 525 mL of 1.00 M HNO3. How many mL of 15.0 M HNO3 will she need for the dilution? ___ mL Your answer should be rounded to the nearest whole number. Do not include units in your answer.

Question

Maria needs to dilute her stock of 15.0 M HNO3 solution for an experiment. She wants to prepare 525 mL of 1.00 M HNO3. How many mL of 15.0 M HNO3 will she need for the dilution?

___ mL

Your answer should be rounded to the nearest whole number. Do not include units in your answer.

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Solution

To solve this problem, we can use the formula M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.

Given: M1 = 15.0 M (initial molarity) M2 = 1.00 M (final molarity) V2 = 525 mL (final volume)

We need to find V1 (initial volume).

Rearranging the formula to solve for V1 gives us V1 = M2V2 / M1.

Substituting the given values into the formula gives us V1 = (1.00 M * 525 mL) / 15.0 M.

Calculating this gives us V1 = 35 mL.

So, Maria will need 35 mL of the 15.0 M HNO3 solution for the dilution.

This problem has been solved

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