Maria needs to dilute her stock of 15.0 M HNO3 solution for an experiment. She wants to prepare 525 mL of 1.00 M HNO3. How many mL of 15.0 M HNO3 will she need for the dilution? ___ mL Your answer should be rounded to the nearest whole number. Do not include units in your answer.
Question
Maria needs to dilute her stock of 15.0 M HNO3 solution for an experiment. She wants to prepare 525 mL of 1.00 M HNO3. How many mL of 15.0 M HNO3 will she need for the dilution?
___ mL
Your answer should be rounded to the nearest whole number. Do not include units in your answer.
Solution
To solve this problem, we can use the formula M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume.
Given: M1 = 15.0 M (initial molarity) M2 = 1.00 M (final molarity) V2 = 525 mL (final volume)
We need to find V1 (initial volume).
Rearranging the formula to solve for V1 gives us V1 = M2V2 / M1.
Substituting the given values into the formula gives us V1 = (1.00 M * 525 mL) / 15.0 M.
Calculating this gives us V1 = 35 mL.
So, Maria will need 35 mL of the 15.0 M HNO3 solution for the dilution.
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