What is the output of the following code snippet?void solve() { stack<int> s; s.push(1); s.push(2); s.push(3); for(int i = 1; i <= 3; i++) { cout << s.top() << “ “; s.pop(); }}
Question
What is the output of the following code snippet?void solve() { stack<int> s; s.push(1); s.push(2); s.push(3); for(int i = 1; i <= 3; i++) { cout << s.top() << “ “; s.pop(); }}
Solution
The output of the code snippet will be "3 2 1 ".
Here's the step by step explanation:
- A stack 's' of integer type is declared.
- The numbers 1, 2, and 3 are pushed onto the stack in that order. The top of the stack is now 3, as stacks follow the Last In First Out (LIFO) principle.
- A for loop is initiated which will run three times, as i ranges from 1 to 3.
- In each iteration of the loop, the top element of the stack is printed and then popped from the stack.
- In the first iteration, 3 is printed and popped.
- In the second iteration, 2 is printed and popped.
- In the third iteration, 1 is printed and popped.
- After the loop has finished executing, all elements have been removed from the stack, and "3 2 1 " has been printed to the console.
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