What is the output of the following snippet? #include <iostream> using namespace std; int main() { int *it[3]; for(int i = 0; i < 3; i++) { it[i] = new int [i + 1]; for(int j = 0; j < i + 1; j++) it[i][j] = 10 * i + j; } cout << it[2][2]; for(int i = 0; i < 3; i++) delete [] it[i]; } 22 11 33 Compilation fails

The output of the given C++ code snippet will be 22.

Here's the step by step explanation:

1. The code declares an array of integer pointers it[3].

2. Then, it enters a loop that iterates three times (i = 0, 1, 2).

3. In each iteration, it allocates a dynamic array of integers of size i + 1 and assigns its address to it[i].

4. Then, it enters another loop that iterates i + 1 times and assigns the value 10 * i + j to each element of the dynamic array.

5. After the loops, it prints the value of the third element of the third dynamic array, which is 10 * 2 + 2 = 22.

6. Finally, it deallocates the dynamic arrays.

So, the correct answer is 22.