If the average cutting speed on a shaper is 15 [m/min] , speed ratio 0.7, work part length is 168 [mm] and both start and end allowances are 1 [mm], raw material width is 77 and start and end allowances are 1 each. Machining time is _______ [sec].Question 3Answer176215911835
Question
If the average cutting speed on a shaper is 15 [m/min] , speed ratio 0.7, work part length is 168 [mm] and both start and end allowances are 1 [mm], raw material width is 77 and start and end allowances are 1 each. Machining time is _______ [sec].Question 3Answer176215911835
Solution
The question seems to be asking for the machining time given certain parameters. Here's how you can calculate it:
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First, convert the cutting speed to mm/sec. Since 1 m = 1000 mm and 1 min = 60 sec, 15 m/min = 15 * 1000 / 60 = 250 mm/sec.
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The total length to be machined is the work part length plus the start and end allowances. So, the total length = 168 mm + 1 mm + 1 mm = 170 mm.
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The cutting speed on the return stroke is the speed ratio times the cutting speed. So, the return speed = 0.7 * 250 mm/sec = 175 mm/sec.
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The time for the cutting stroke is the total length divided by the cutting speed. So, the cutting time = 170 mm / 250 mm/sec = 0.68 sec.
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The time for the return stroke is the total length divided by the return speed. So, the return time = 170 mm / 175 mm/sec = 0.97 sec.
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The total machining time is the sum of the cutting time and the return time. So, the machining time = 0.68 sec + 0.97 sec = 1.65 sec.
Therefore, the machining time is approximately 1.65 seconds.
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