Knowee
Questions
Features
Study Tools

If the average cutting speed on a shaper is 8.8 [m/min] , stroke length is 363 [mm] and both start and end allowances are 3 [mm]. The stroke cutting time is _______ [sec]

Question

If the average cutting speed on a shaper is 8.8 [m/min] , stroke length is 363 [mm] and both start and end allowances are 3 [mm]. The stroke cutting time is _______ [sec]

🧐 Not the exact question you are looking for?Go ask a question

Solution 1

To calculate the stroke cutting time, we need to follow these steps:

  1. Convert the stroke length and allowances from millimeters to meters: Stroke length = 363 mm = 0.363 m Start allowance = End allowance = 3 mm = 0.003 m

  2. Add the stroke length and both allowances to get the total distance covered in one stroke: Total distance = Stroke length + Start allowance + End allowance Total distance = 0.363 m + 0.003 m + 0.003 m = 0.369 m

  3. Convert the cutting speed from meters per minute to meters per second:

This problem has been solved

Solution 2

To find the stroke cutting time, we need to follow these steps:

  1. Convert all measurements to the same units. In this case, we'll convert meters to millimeters because the stroke length and allowances are given in millimeters. So, the cutting speed is 8.8 m/min * 1000 = 8800 mm/min.

  2. Calculate the total distance of the stroke. This is the stroke length plus the start and end allowances. So, the total distance is 363 mm + 3 mm + 3 mm = 369 mm.

  3. Now, we can find the time it takes to complete one stroke. The time is the total distance divided by the speed. So, the time is 369 mm / 8800 mm/min = 0.04193 minutes.

  4. Finally, convert this time from minutes to seconds. There are 60 seconds in a minute, so the time is 0.04193 min * 60 = 2.5158 seconds.

So, the stroke cutting time is approximately 2.52 seconds.

This problem has been solved

Similar Questions

If the average cutting speed on a shaper is 15 [m/min] , speed ratio 0.7, work part length is 168 [mm] and both start and end allowances are 1 [mm], raw material width is 77 and start and end allowances are 1 each.  Machining time is _______ [sec].Question 3Answer176215911835

The rate at which the cutting edge of a tool moves through metal, measured in feet per minute (or meters per minute) is the definition of?

A straight turning process reduces the diameter of a cylindrical work part from 121 to 107 [mm]. The feed rate is set at 0.15 [mm/rev]. The cutting speed is set at 39 [m/min].  The work part material has a specific cutting energy of 1.5 [W.s/mm3].  Machining power in [KW] is then given by: Question 7Answer1.020.0616.672.051023.75

Consider milling a 31 [mm] depth slot in aflat surface of a work part using a slab milling cutter. The diameter of the cutter is 76 [mm], its width is 44 [mm] and it has 9 teeth. The cutter rotates at 576 [RPM]. Measurement of the chip thickness shows that feed rate is 0.02 [mm/tooth]. The length of the work part is 284 [mm]. The allowances at the beginning and end of the cut are 3 [mm]. MRR in [mm3/sec] is then given by  _______ Question 1Answer20831906206420451831

An analyst has timed a metal-cutting task for 50 cycles. The average time per cycle was 11.9 minutes, and the standard deviation was 1.32 minutes for a worker with a performance rating of 130 percent. Assume an allowance of 17 percent of task time. Calculate the standard time for this task. (Do not round intermediate calculations. Round the final answer to 2 decimal places.)

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.