How many grams of nitrogen is approximately present in every 100 g of ammonium sulphate(NH4)2SO4?

To find out how many grams of nitrogen are present in 100g of ammonium sulphate (NH4)2SO4, we need to follow these steps:

1. First, we need to find the molar mass of ammonium sulphate. The molar mass of nitrogen (N) is approximately 14g/mol, hydrogen (H) is approximately 1g/mol, sulphur (S) is approximately 32g/mol, and oxygen (O) is approximately 16g/mol.

   In ammonium sulphate, there are 2 nitrogen atoms, 8 hydrogen atoms, 1 sulphur atom, and 4 oxygen atoms.

   So, the molar mass of ammonium sulphate is (214) + (81) + 32 + (4*16) = 132 g/mol.

2. Next, we need to find out how much nitrogen is there in one mole of ammonium sulphate. Since there are 2 nitrogen atoms in one molecule of ammonium sulphate, there are 2 moles of nitrogen in one mole of ammonium sulphate.

   So, the mass of nitrogen in one mole of ammonium sulphate is 2*14 = 28g.

3. Now, we need to find out how much nitrogen is there in 100g of ammonium sulphate.

   To do this, we set up a proportion: (28g nitrogen / 132g ammonium sulphate) = (x g nitrogen / 100g ammonium sulphate)

   Solving for x gives us x = (28*100) / 132 = 21.21g

So, there are approximately 21.21g of nitrogen in every 100g of ammonium sulphate.