If a body moving with initial, constant velocity of 10 m s¹, accelerates for 2 seconds at a constant rate of 12 m s², final velocity of body will be a) 30 m s¹ b) 34 m s-¹ c) 40 m s-¹ d) 45 m s-
Question
If a body moving with initial, constant velocity of 10 m s¹, accelerates for 2 seconds at a constant rate of 12 m s², final velocity of body will be a) 30 m s¹ b) 34 m s-¹ c) 40 m s-¹ d) 45 m s-
Solution
The final velocity of a body can be calculated using the equation:
v = u + at
where: v = final velocity u = initial velocity a = acceleration t = time
Given in the problem: u = 10 m/s a = 12 m/s² t = 2 s
Substituting these values into the equation:
v = 10 m/s + (12 m/s² * 2 s)
v = 10 m/s + 24 m/s
v = 34 m/s
So, the final velocity of the body will be 34 m/s. Therefore, the correct answer is b) 34 m/s.
Similar Questions
What is the acceleration of an object that is initially moving at 10.5m/s and is moving at 13.5m/s after 2.0s?
A body moving along a straight line at 20 m/s undergoes an acceleration of 4 m/s2. After 2 s its speed will be (a) 8 m/s (b)10 m/s (c)16 m/s (d)28 m/s
The acceleration 'a' in m/s2 of a particle is given by a = 3t2 + 2t + 2 where t is the time. If the particle starts out with a velocity, u = 2 m/s at t = 0, then the velocity at the end of 2 seconds will be :12 m/s18 m/s27 m/s36 m/s
A particle moves rectilinearly with a constant acceleration 1 m/s2. Its speed after 10 seconds is 5 m/s. The distance covered by the particle in this duration is (Initial & final velocities are in opposite direction)
A body is accelerated from rest by applying a force of 30N. The momentum of the body after 2 seconds isA.7.5 kg-m/sB.30 kg-m/sC.120 kg-m/sD.60 kg-m/s
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.