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A body is accelerated from rest by applying a force of 30N. The momentum of the body after 2 seconds isA.7.5 kg-m/sB.30 kg-m/sC.120 kg-m/sD.60 kg-m/s

Question

A body is accelerated from rest by applying a force of 30N. The momentum of the body after 2 seconds isA.7.5 kg-m/sB.30 kg-m/sC.120 kg-m/sD.60 kg-m/s

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Solution

To solve this problem, we need to use the second law of motion, which states that the force applied on an object is equal to the change in its momentum over time. Mathematically, this is represented as F = Δp/Δt, where F is the force, Δp is the change in momentum, and Δt is the change in time.

Given in the problem, we have:

F = 30N Δt = 2s

We need to find Δp, which is the momentum of the body after 2 seconds.

Rearranging the formula, we get Δp = F * Δt.

Substituting the given values, we get Δp = 30N * 2s = 60 kg-m/s.

So, the momentum of the body after 2 seconds is 60 kg-m/s. Therefore, the correct answer is D.60 kg-m/s.

This problem has been solved

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