The total distance travelled by the body can be calculated by adding the distances travelled in each phase of the motion.

1. During the first phase, the body accelerates uniformly from rest. The distance travelled can be calculated using the equation of motion: s = ut + 0.5at^2. Here, u is the initial velocity (0 m/s), a is the acceleration (10 m/s^2), and t is the time (5s). So, s1 = 0*5 + 0.5*10*5^2 = 125 m.

2. In the second phase, the body moves with a uniform velocity. The distance travelled is simply the product of velocity and time: s = vt. Here, v is the velocity (50 m/s) and t is the time (2s). So, s2 = 50*2 = 100 m.

3. In the third phase, the body decelerates uniformly to rest. The distance travelled can be calculated using the equation of motion: v^2 = u^2 + 2as. Here, v is the final velocity (0 m/s), u is the initial velocity (50 m/s), and a is the deceleration (-50/3 m/s^2). Solving for s gives s3 = (0 - 50^2) / (2*-50/3) = 75 m.

Adding these distances together gives the total distance travelled: s = s1 + s2 + s3 = 125 m + 100 m + 75 m = 300 m.

So, the correct answer is B) 300 m.

Question

The total distance travelled by the body can be calculated by adding the distances travelled in each phase of the motion.

1. During the first phase, the body accelerates uniformly from rest. The distance travelled can be calculated using the equation of motion: s = ut + 0.5at^2. Here, u is the initial velocity (0 m/s), a is the acceleration (10 m/s^2), and t is the time (5s). So, s1 = 0*5 + 0.5*10*5^2 = 125 m.

2. In the second phase, the body moves with a uniform velocity. The distance travelled is simply the product of velocity and time: s = vt. Here, v is the velocity (50 m/s) and t is the time (2s). So, s2 = 50*2 = 100 m.

3. In the third phase, the body decelerates uniformly to rest. The distance travelled can be calculated using the equation of motion: v^2 = u^2 + 2as. Here, v is the final velocity (0 m/s), u is the initial velocity (50 m/s), and a is the deceleration (-50/3 m/s^2). Solving for s gives s3 = (0 - 50^2) / (2*-50/3) = 75 m.

Adding these distances together gives the total distance travelled: s = s1 + s2 + s3 = 125 m + 100 m + 75 m = 300 m.

So, the correct answer is B) 300 m.

Knowee AI · Accepted Answer

The total distance travelled by the body can be calculated by adding the distances travelled in each phase of the motion.

1. During the first phase, the body accelerates uniformly from rest. The distance travelled can be calculated using the equation of motion: s = ut + 0.5at^2. Here, u is the initial velocity (0 m/s), a is the acceleration (10 m/s^2), and t is the time (5s). So, s1 = 0*5 + 0.5*10*5^2 = 125 m.

2. In the second phase, the body moves with a uniform velocity. The distance travelled is simply the product of velocity and time: s = vt. Here, v is the velocity (50 m/s) and t is the time (2s). So, s2 = 50*2 = 100 m.

3. In the third phase, the body decelerates uniformly to rest. The distance travelled can be calculated using the equation of motion: v^2 = u^2 + 2as. Here, v is the final velocity (0 m/s), u is the initial velocity (50 m/s), and a is the deceleration (-50/3 m/s^2). Solving for s gives s3 = (0 - 50^2) / (2*-50/3) = 75 m.

Adding these distances together gives the total distance travelled: s = s1 + s2 + s3 = 125 m + 100 m + 75 m = 300 m.

So, the correct answer is B) 300 m.

A body starting from rest accelerates uniformly by along a straight line at the rate of 10 m/s2 for 5s. It moves for 2s with uniform velocity of 50 m/s. Then it retards uniformly and comes to rest in 3s. The total distance travelled by the body is:A 200 m B 300 m C 400 m D 600 m

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