A is two years older than B who is twice as old as C. If the total of the ages of A, B and C are 27, then how old is B?
Question
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C are 27, then how old is B?
Solution
Let's solve this step by step:
- Let's assume the age of C is x.
- According to the given information, B is twice as old as C, so B's age is 2x.
- A is two years older than B, so A's age is 2x + 2.
- The total of the ages of A, B, and C is 27, so we can write the equation: x + 2x + (2x + 2) = 27.
- Simplifying the equation, we get 5x + 2 = 27.
- Subtracting 2 from both sides, we have 5x = 25.
- Dividing both sides by 5, we find x = 5.
- Now that we know the age of C is 5, we can find the age of B by substituting it into the equation for B's age: B = 2x = 2 * 5 = 10.
Therefore, B is 10 years old.
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