The ratio of the ages of A,B and C is 7:5:4. If C’s age is 32 years, the sum of the age of A, B and Ca.128b. 120c.56d.49
Question
The ratio of the ages of A,B and C is 7:5:4. If C’s age is 32 years, the sum of the age of A, B and Ca.128b. 120c.56d.49
Solution
The problem states that the ratio of the ages of A, B, and C is 7:5:4 and that C's age is 32 years.
Step 1: Understand the ratio The ratio means that for every 7 years that A is old, B is 5 years old, and C is 4 years old.
Step 2: Find the total parts in the ratio The total parts in the ratio are 7 (for A) + 5 (for B) + 4 (for C) = 16 parts.
Step 3: Find the value of one part We know that C's age is 32 years and that corresponds to 4 parts in the ratio. So, one part in the ratio is 32 years / 4 = 8 years.
Step 4: Find the ages of A and B A's age is 7 parts * 8 years/part = 56 years. B's age is 5 parts * 8 years/part = 40 years.
Step 5: Find the sum of the ages of A, B, and C The sum of the ages of A, B, and C is 56 years (for A) + 40 years (for B) + 32 years (for C) = 128 years.
So, the answer is a. 128.
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