Let's solve this step by step:

Step 1: Let's denote the present age of A as 'a', B as 'b', C as 'c', and D as 'd'.

Step 2: From the problem, we know that B is 1/4 times more than the age of A. So, we can write this as: b = a + a/4 = 5a/4.

Step 3: We also know that the average age of A and B is 22.5 years. So, (a + b)/2 = 22.5. Substituting the value of b from step 2, we get: (a + 5a/4)/2 = 22.5. Solving this, we get a = 20.

Step 4: Substituting a = 20 in b = 5a/4, we get b = 25.

Step 5: The problem also states that 5 years ago, the sum of the ages of B and C was 50 years. So, (b - 5) + (c - 5) = 50. Substituting b = 25, we get c = 35.

Step 6: The problem states that after 6 years, the age of D will be 1/5 times more than C’s age at present. So, d + 6 = c + c/5 = 42. Solving this, we get d = 36.

Step 7: Now, we need to find the ratio of the sum of present ages of B and C to that of A and D. So, (b + c) : (a + d) = (25 + 35) : (20 + 36) = 60 : 56 = 15 : 14.

So, the answer is option b. 15 : 14.

Question

Let's solve this step by step:

Step 1: Let's denote the present age of A as 'a', B as 'b', C as 'c', and D as 'd'.

Step 2: From the problem, we know that B is 1/4 times more than the age of A. So, we can write this as: b = a + a/4 = 5a/4.

Step 3: We also know that the average age of A and B is 22.5 years. So, (a + b)/2 = 22.5. Substituting the value of b from step 2, we get: (a + 5a/4)/2 = 22.5. Solving this, we get a = 20.

Step 4: Substituting a = 20 in b = 5a/4, we get b = 25.

Step 5: The problem also states that 5 years ago, the sum of the ages of B and C was 50 years. So, (b - 5) + (c - 5) = 50. Substituting b = 25, we get c = 35.

Step 6: The problem states that after 6 years, the age of D will be 1/5 times more than C’s age at present. So, d + 6 = c + c/5 = 42. Solving this, we get d = 36.

Step 7: Now, we need to find the ratio of the sum of present ages of B and C to that of A and D. So, (b + c) : (a + d) = (25 + 35) : (20 + 36) = 60 : 56 = 15 : 14.

So, the answer is option b. 15 : 14.

Knowee AI · Accepted Answer

Let's solve this step by step:

Step 1: Let's denote the present age of A as 'a', B as 'b', C as 'c', and D as 'd'.

Step 2: From the problem, we know that B is 1/4 times more than the age of A. So, we can write this as: b = a + a/4 = 5a/4.

Step 3: We also know that the average age of A and B is 22.5 years. So, (a + b)/2 = 22.5. Substituting the value of b from step 2, we get: (a + 5a/4)/2 = 22.5. Solving this, we get a = 20.

Step 4: Substituting a = 20 in b = 5a/4, we get b = 25.

Step 5: The problem also states that 5 years ago, the sum of the ages of B and C was 50 years. So, (b - 5) + (c - 5) = 50. Substituting b = 25, we get c = 35.

Step 6: The problem states that after 6 years, the age of D will be 1/5 times more than C’s age at present. So, d + 6 = c + c/5 = 42. Solving this, we get d = 36.

Step 7: Now, we need to find the ratio of the sum of present ages of B and C to that of A and D. So, (b + c) : (a + d) = (25 + 35) : (20 + 36) = 60 : 56 = 15 : 14.

So, the answer is option b. 15 : 14.

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