A is 2 years older than B who is twice as old as C.If sum of ages of A,B and C is 37 years.Find the age of A.16 years17 years18 years19 yearsClear ResponseSave & Next
Question
A is 2 years older than B who is twice as old as C.If sum of ages of A,B and C is 37 years.Find the age of A.16 years17 years18 years19 yearsClear ResponseSave & Next
Solution
Let's denote the age of C as x.
According to the problem, B is twice as old as C, so B = 2x.
A is 2 years older than B, so A = 2x + 2.
The sum of their ages is 37, so we can set up the following equation:
x + 2x + 2x + 2 = 37
Solving this equation gives us:
5x + 2 = 37
Subtract 2 from both sides:
5x = 35
Divide both sides by 5:
x = 7
So, C is 7 years old.
B is twice as old as C, so B = 2 * 7 = 14 years old.
A is 2 years older than B, so A = 14 + 2 = 16 years old.
So, the age of A is 16 years.
Similar Questions
Sum of present ages of A, B and C is 72 years. If 4 years ago, their ages were in the ratio of 1 : 2 : 3, find A's present ageA7 YearsB10 YearsC12 YearsD14 Years
A is two years older than B who is twice as old as C. If the total of the ages of A, B and C are 27, then how old is B?
The half of the sum of the ages of A and B is 5 years more than the age of C. The sum of ages of B and C is 10 years more than the age of A. If the age of A is 42 years, then find the age of B.
elect the correct answerAverage age of A, B and C is 10 year less than age of C. If ratio of age of A, B and C is 3 : 4 : 5 then what is the sum of age of A & C ?Options85 year72 year80 year78 year
The product of the ages of A and B is 240. If twice the age of B is more than A’s age by 4 years, what was B’s age 2 years ago?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.