According to the Saytzeff/Zaitsev rule, which is the most likely major product upon dehydration of 3-methyl-2-butanol?Select your answer:Select your answerOPTION ALTERNATIVE 3-methylbut-2-ene 2-methylbut-1-ene 3-methylbut-1-ene 3-methylbutane 2-methylbut-2-ene
Question
According to the Saytzeff/Zaitsev rule, which is the most likely major product upon dehydration of 3-methyl-2-butanol?Select your answer:Select your answerOPTION ALTERNATIVE 3-methylbut-2-ene 2-methylbut-1-ene 3-methylbut-1-ene 3-methylbutane 2-methylbut-2-ene
Solution
The Saytzeff or Zaitsev rule states that in an elimination reaction, the most substituted product will be the most stable, and therefore, the major product.
Here's how to apply it to this problem:
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Identify the molecule: 3-methyl-2-butanol is a 5-carbon chain with a hydroxyl (-OH) group on the second carbon and a methyl group on the third carbon.
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Identify the type of reaction: Dehydration is an elimination reaction where a molecule of water is removed from the substrate. In this case, the -OH group and a hydrogen atom from the adjacent carbon will be removed.
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Apply the Saytzeff/Zaitsev rule: The rule predicts that the major product of the reaction will be the alkene with the most substituted double bond. This means the double bond should be located between the second and third carbons, where it will be attached to three other carbon atoms.
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Identify the product: The product that fits this description is 2-methylbut-2-ene.
So, the most likely major product upon dehydration of 3-methyl-2-butanol, according to the Saytzeff/Zaitsev rule, is 2-methylbut-2-ene.
Similar Questions
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