OperatorsWhat will be the output of the following code segment?int x = 24, y = 39, z = 45;z = x + y;y = z - y;x = z - y;printf("%d %d %d", x, y, z);Options24 39 6339 24 6324 39 4539 24 45
Question
OperatorsWhat will be the output of the following code segment?int x = 24, y = 39, z = 45;z = x + y;y = z - y;x = z - y;printf("%d %d %d", x, y, z);Options24 39 6339 24 6324 39 4539 24 45
Solution
The output of the code segment will be 39 24 63.
Here's the step by step explanation:
- The initial values are x = 24, y = 39, z = 45.
- The first operation is z = x + y, which results in z = 63.
- The second operation is y = z - y, which results in y = 24.
- The third operation is x = z - y, which results in x = 39.
- The printf statement prints the values of x, y, and z, which are 39, 24, and 63 respectively.
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