What is the output of this C code?#include <stdio.h>void main(){int x = 5, y = -7, z = 0, d;d = ++x && ++y || ++z;printf("\n%d%d%d%d", x,  y, z, d);}6 -6 0 06 -5 0 1-6 -6 0 16 -6 0 1

The output of the given C code will be "6 -6 1 1".

Here's the step by step explanation:

1. The ++x operation increments x by 1, making x equal to 6. Since x is not zero, the result of this operation is true.

2. The ++y operation increments y by 1, making y equal to -6. Since y is not zero, the result of this operation is also true.

3. The && operator performs a logical AND operation. Since both x and y are true, the result of the && operation is true.

4. The || operator performs a logical OR operation. The left side of the || operator is true, so the ++z operation is not performed (this is known as short-circuit evaluation). Therefore, z remains 0.

5. The result of the || operation is true, so d is set to 1.

6. The printf function prints the values of x, y, z, and d, resulting in "6 -6 0 1".