What will be the output of the following C code?#include <stdio.h>int main() {    int i;    for (i = 0; i < 5; i++);    printf("%d\n", i);    return 0;}

The output of the given C code will be "5".

Here's the step by step explanation:

1. The program starts with the inclusion of the standard input/output library using #include <stdio.h>.

2. The main() function is declared, which is the entry point of the program.

3. Inside the main() function, an integer i is declared.

4. A for loop is initiated where i is set to 0 and the condition is i < 5. The loop increments i by 1 (i++) each time it runs. However, there is no code to execute within the loop (indicated by the semicolon ; right after the loop) so it simply increments i from 0 to 5.

5. Once i equals 5, the condition i < 5 is no longer true, so the loop ends.

6. The printf function is then called to print the value of i, which is now 5, followed by a newline character \n.

7. The program then returns 0, indicating successful execution, and ends.