What will be the output of the following code snippet?123456#include <stdio.h> int main() { int a = 10, b = 4; printf("%d", a - b * 2); }

The output of the code will be 2.

Here's the step by step explanation:

1. The code declares two integer variables, a and b, and assigns them the values 10 and 4 respectively.
2. The printf function is called to print the result of the expression a - b * 2.
3. The expression b * 2 is evaluated first due to operator precedence. Multiplication has higher precedence than subtraction. So, 4 * 2 equals 8.
4. Then, the result of a - 8 is calculated, which equals 2.
5. Therefore, the output of the code is 2.