A solution is prepared by dissolving 5.00 g of LiCl to a total volume of 200.0 cm3. Calculate the molar concentration of this solution.

Sure, here are the steps to calculate the molar concentration of the solution:

1. First, we need to find the molar mass of LiCl. The atomic mass of Li (Lithium) is approximately 6.94 g/mol and the atomic mass of Cl (Chlorine) is approximately 35.45 g/mol. So, the molar mass of LiCl is 6.94 g/mol + 35.45 g/mol = 42.39 g/mol.

2. Next, we calculate the number of moles of LiCl in the 5.00 g of LiCl that was dissolved. We use the formula: moles = mass / molar mass. So, moles of LiCl = 5.00 g / 42.39 g/mol = 0.118 mol.

3. The volume of the solution is given as 200.0 cm3. We need to convert this to liters because molar concentration is expressed in mol/L. 1 cm3 is equal to 0.001 L, so 200.0 cm3 = 200.0 * 0.001 L = 0.2 L.

4. Finally, we calculate the molar concentration of the solution using the formula: molar concentration = moles / volume. So, molar concentration of LiCl = 0.118 mol / 0.2 L = 0.59 mol/L.

So, the molar concentration of the solution is 0.59 mol/L.