SLHLDifficulty: Multiple choice questionA solution is prepared by dissolving 5.00 g of LiCl to a total volume of 200.0 cm3. Calculate the molar concentration of this solution.

Sure, here are the steps to calculate the molar concentration of the solution:

1. First, we need to find the molar mass of LiCl. The atomic mass of Li (Lithium) is approximately 6.94 g/mol and the atomic mass of Cl (Chlorine) is approximately 35.45 g/mol. So, the molar mass of LiCl is 6.94 g/mol + 35.45 g/mol = 42.39 g/mol.

2. Next, we convert the mass of LiCl used to moles. We know that we used 5.00 g of LiCl. So, the number of moles of LiCl is 5.00 g ÷ 42.39 g/mol = 0.118 mol (rounded to three decimal places).

3. Then, we convert the volume of the solution from cm3 to L because molar concentration is usually expressed in mol/L. We know that 1 cm3 is equal to 0.001 L. So, 200.0 cm3 is equal to 200.0 cm3 × 0.001 L/cm3 = 0.200 L.

4. Finally, we calculate the molar concentration of the solution by dividing the number of moles of LiCl by the volume of the solution in L. So, the molar concentration is 0.118 mol ÷ 0.200 L = 0.590 mol/L (rounded to three decimal places).

So, the molar concentration of the solution is approximately 0.590 mol/L.