What is the molar concentration of a NaCl solution prepared by dissolving 9.27 g of NaCl in sufficient water to give 350 mL of solution?Question 14Select one:a.18 mol L-1b.0.16 mol L-1c.0.45 mol L-1d.27 mol L-1e.2.7 x 10-2 mol L-1

To solve this problem, we need to follow these steps:

1. First, we need to convert the mass of NaCl to moles. The molar mass of NaCl is approximately 58.44 g/mol. So, we divide the given mass by the molar mass:

   9.27 g / 58.44 g/mol = 0.1586 mol

2. Next, we need to convert the volume of the solution from mL to L, because molar concentration is expressed in mol/L.

   350 mL = 0.35 L

3. Finally, we calculate the molar concentration by dividing the number of moles of NaCl by the volume of the solution in liters:

   0.1586 mol / 0.35 L = 0.453 mol/L

So, the molar concentration of the NaCl solution is approximately 0.45 mol/L. Therefore, the correct answer is c. 0.45 mol L-1.