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How much energy is required to raise the temperature of a 300.0 gram block of lead from 22.3°C to 59.9°C? The specific heat of lead is 0.129 J/g°C. Round your answer to the nearest whole number. a 1756 joules b 1392 joules c 1455 joules d 1275 joules

Question

How much energy is required to raise the temperature of a 300.0 gram block of lead from 22.3°C to 59.9°C? The specific heat of lead is 0.129 J/g°C.

Round your answer to the nearest whole number.

a 1756 joules

b 1392 joules

c 1455 joules

d 1275 joules

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Solution

To solve this problem, we need to use the formula for heat transfer:

Q = mcΔT

where: Q = heat energy (Joules) m = mass (grams) c = specific heat capacity (Joules/gram°C) ΔT = change in temperature (°C)

Given: m = 300.0 g c = 0.129 J/g°C ΔT = 59.9°C - 22.3°C = 37.6°C

Substitute the given values into the formula:

Q = (300.0 g)(0.129 J/g°C)(37.6°C)

Q = 1455.68 J

Rounding to the nearest whole number, we get Q = 1456 J.

So, the correct answer is:

c 1455 joules

This problem has been solved

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