How much energy is required to raise the temperature of a 300.0 gram block of lead from 22.3°C to 59.9°C? The specific heat of lead is 0.129 J/g°C. Round your answer to the nearest whole number. a 1756 joules b 1392 joules c 1455 joules d 1275 joules
Question
How much energy is required to raise the temperature of a 300.0 gram block of lead from 22.3°C to 59.9°C? The specific heat of lead is 0.129 J/g°C.
Round your answer to the nearest whole number.
a 1756 joules
b 1392 joules
c 1455 joules
d 1275 joules
Solution
To solve this problem, we need to use the formula for heat transfer:
Q = mcΔT
where: Q = heat energy (Joules) m = mass (grams) c = specific heat capacity (Joules/gram°C) ΔT = change in temperature (°C)
Given: m = 300.0 g c = 0.129 J/g°C ΔT = 59.9°C - 22.3°C = 37.6°C
Substitute the given values into the formula:
Q = (300.0 g)(0.129 J/g°C)(37.6°C)
Q = 1455.68 J
Rounding to the nearest whole number, we get Q = 1456 J.
So, the correct answer is:
c 1455 joules
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