The energy needed to increase the temperature of 1.5 kg of lead by 20 °C was 3.9 kJ.Calculate the specific heat capacity of lead._________ J/kg°CYou do not need to give units in your answer.
Question
The energy needed to increase the temperature of 1.5 kg of lead by 20 °C was 3.9 kJ.Calculate the specific heat capacity of lead._________ J/kg°CYou do not need to give units in your answer.
Solution
The specific heat capacity (c) can be calculated using the formula:
Q = mcΔT
where: Q = heat energy absorbed or released (in joules or J) m = mass of the substance (in kilograms or kg) c = specific heat capacity (in joules per kilogram per degree Celsius or J/kg°C) ΔT = change in temperature (in degrees Celsius or °C)
In this case, we are given: Q = 3.9 kJ = 3900 J (since 1 kJ = 1000 J) m = 1.5 kg ΔT = 20 °C
We are asked to find c. Rearranging the formula to solve for c gives:
c = Q / (mΔT)
Substituting the given values into the formula gives:
c = 3900 J / (1.5 kg * 20 °C) = 130 J/kg°C
So, the specific heat capacity of lead is 130 J/kg°C.
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