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What does this code print?void print(int nb){ printf("%d", nb); -- nb; if (nb > 0) { print(nb); }}int main(void){ print(4); return (0);}

Question

What does this code print?void print(int nb){ printf("%d", nb); -- nb; if (nb > 0) { print(nb); }}int main(void){ print(4); return (0);}

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Solution

This code will print "4321".

Here's the step-by-step explanation:

  1. The main function calls the print function with the argument 4.
  2. The print function prints the number 4 and then decrements it by 1.
  3. Since the number 3 is greater than 0, the print function is called again with the argument 3.
  4. This process repeats until the number 1 is printed and decremented to 0.
  5. Since 0 is not greater than 0, the print function is not called again and the program ends.

So, the output of the program is the string "4321".

This problem has been solved

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