What does the following program print?#include <stdio.h>int main() {    for (int i = 1; i < 10; i++) {        if (i % 2 == 0)            continue;        printf("%d ", i);    }    return 0;}

The program prints the odd numbers from 1 to 9. Here's how it works:

1. The for loop initializes i to 1 and will continue as long as i is less than 10, incrementing i by 1 after each loop.

2. Inside the loop, the if statement checks if i is divisible by 2 (i.e., if i is an even number). If it is, the continue statement is executed. This skips the rest of the current iteration and goes straight to the next iteration of the loop.

3. If i is not divisible by 2 (i.e., if i is an odd number), the program skips the if statement and executes the printf statement, which prints the value of i followed by a space.

4. This process repeats until i is no longer less than 10.

So, the output of the program is: 1 3 5 7 9