What does this code print?* print_something - function to print something** Return: Always 0**/int print_something(int num){ int i, j; for (i = 0; i < num + 1; i++) { for (j = 0; j < num + 1; j++) { printf("%d", i * j); if (j < num) { printf(", "); } } printf("\n"); } return (0);}
Question
What does this code print?* print_something - function to print something** Return: Always 0**/int print_something(int num){ int i, j; for (i = 0; i < num + 1; i++) { for (j = 0; j < num + 1; j++) { printf("%d", i * j); if (j < num) { printf(", "); } } printf("\n"); } return (0);}
Solution
This code is written in C language. It defines a function named print_something that takes an integer num as an argument.
Here's a step-by-step explanation of what the code does:
-
The function
print_somethingis defined with one parameternum. -
Two integer variables
iandjare declared. -
A
forloop is initiated withistarting from 0 and running untiliis less than or equal tonum. -
Inside this
forloop, anotherforloop is initiated withjstarting from 0 and running untiljis less than or equal tonum. -
Inside the inner
forloop, the product ofiandjis printed. -
If
jis less thannum, a comma followed by a space is printed. -
After the inner
forloop finishes (i.e., for eachi), a newline character is printed. -
Finally, the function returns 0.
So, if you call print_something(2), for example, the output will be:
0, 0, 0
0, 1, 2
0, 2, 4
This is because the function prints a multiplication table for the numbers from 0 to num.
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