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What does this code print?* print_something - function to print something** Return: Always 0**/int print_something(int num){ int i, j; for (i = 0; i < num + 1; i++) { for (j = 0; j < num + 1; j++) { printf("%d", i * j); if (j < num) { printf(", "); } } printf("\n"); } return (0);}

Question

What does this code print?* print_something - function to print something** Return: Always 0**/int print_something(int num){ int i, j; for (i = 0; i < num + 1; i++) { for (j = 0; j < num + 1; j++) { printf("%d", i * j); if (j < num) { printf(", "); } } printf("\n"); } return (0);}

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Solution

This code is written in C language. It defines a function named print_something that takes an integer num as an argument.

Here's a step-by-step explanation of what the code does:

  1. The function print_something is defined with one parameter num.

  2. Two integer variables i and j are declared.

  3. A for loop is initiated with i starting from 0 and running until i is less than or equal to num.

  4. Inside this for loop, another for loop is initiated with j starting from 0 and running until j is less than or equal to num.

  5. Inside the inner for loop, the product of i and j is printed.

  6. If j is less than num, a comma followed by a space is printed.

  7. After the inner for loop finishes (i.e., for each i), a newline character is printed.

  8. Finally, the function returns 0.

So, if you call print_something(2), for example, the output will be:

0, 0, 0
0, 1, 2
0, 2, 4

This is because the function prints a multiplication table for the numbers from 0 to num.

This problem has been solved

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