Consider the following code snippet. What is the output?#include <stdio.h>int main() {    int arr[5] = {1, 2};    for (int i = 0; i < 5; i++) {        printf("%d ", arr[i]);    }    return 0;}

The output of the code will be:

1 2 0 0 0

Here's the step by step explanation:

1. An integer array of size 5 is declared and initialized with the values 1 and 2 at the first two indices. The rest of the indices are not explicitly initialized.

2. In C, when an array is partially initialized, like in this case, the rest of the elements get automatically initialized to 0.

3. A for loop is used to iterate over the array from index 0 to 4.

4. Inside the loop, the value at each index of the array is printed.

5. Therefore, it prints 1 and 2 for the first two indices and 0 for the rest of the indices.