find recurrence relation an-4an-1=0

The solution of the recursion relation an=8a(n-1)-16a(n-2), with a0=1 and a1=6 is an=_________.Question 6Answera.(1+n)4nb.(1+  n) 4nc.(1+2n)4nd.4(n+1)

What is the recursive formula for this geometric sequence?–4, –24, –144, –864, ...A.{𝑎1=−6𝑎𝑛=𝑎𝑛−1∙4{ a 1​ =−6a n​ =a n−1​ ∙4​ B.{𝑎1=−4𝑎𝑛=𝑎𝑛−1∙6{ a 1​ =−4a n​ =a n−1​ ∙6​ C.{𝑎1=−4𝑎𝑛=𝑎𝑛−1∙30{ a 1​ =−4a n​ =a n−1​ ∙30​ D.{𝑎1=−6𝑎𝑛=𝑎𝑛−1∙30{ a 1​ =−6a n​ =a n−1​ ∙30​

The solution to the recurrence relation an=3a(n-1)-  a(n-2), where a0=1 and a1=3, then an= ________.Question 26Answera.(1-n)b.(n-2)c.(1+n)d.2n ⋅

Find the closed form of the generating function of the sequence an=3n−4 , n=0, 1, 2, ….

4. Find the solution to each of these recurrence relations and initial conditions.a) an = −an−1, a0 = 5 b) an = an−1 + 3, a0 = 1 c) an = an−1 − n, a0 = 4d ) an = 2nan−1, a0 = 3 e) an = 5an−1 − 6an−2, a0 = 2, a1 = −1