The solution of the recursion relation an=8a(n-1)-16a(n-2), with a0=1 and a1=6 is an=_________.Question 6Answera.(1+n)4nb.(1+  n) 4nc.(1+2n)4nd.4(n+1)

The solution to the recurrence relation an=3a(n-1)-  a(n-2), where a0=1 and a1=3, then an= ________.Question 26Answera.(1-n)b.(n-2)c.(1+n)d.2n ⋅

Which recursive formula can be used to represent the sequence 2, 4, 6, 8, 10, ... ?A.𝑎1=0𝑎𝑛=𝑎𝑛−1+2​ a 1​ =0a n​ =a n−1​ +2​ B.𝑎1=2𝑎𝑛=𝑎𝑛−1∙2​ a 1​ =2a n​ =a n−1​ ∙2​ C.𝑎1=2𝑎𝑛=𝑎𝑛−1+2​ a 1​ =2a n​ =a n−1​ +2​ D.𝑎1=2𝑎𝑛=𝑎𝑛−1−2​ a 1​ =2a n​ =a n−1​ −2​ SUBMITarrow_backPREVIOUS

What is the recursive formula for this geometric sequence?–4, –24, –144, –864, ...A.{𝑎1=−6𝑎𝑛=𝑎𝑛−1∙4{ a 1​ =−6a n​ =a n−1​ ∙4​ B.{𝑎1=−4𝑎𝑛=𝑎𝑛−1∙6{ a 1​ =−4a n​ =a n−1​ ∙6​ C.{𝑎1=−4𝑎𝑛=𝑎𝑛−1∙30{ a 1​ =−4a n​ =a n−1​ ∙30​ D.{𝑎1=−6𝑎𝑛=𝑎𝑛−1∙30{ a 1​ =−6a n​ =a n−1​ ∙30​

find recurrence relation an-4an-1=0

Find the first four terms of the sequence defined below, where n represents the position of a term in the sequence. Start with n = 1.an = 6n2 + 9n − 6