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Given ∆ABC with vertices at A(-2, 2), B(2, 5), and C(2, 0) and a first transformation of 4 units to the right and 4 units up, and a second transformation of 2 units to the left and 5 units down. What would be the location of the final B''?

Question

Given ∆ABC with vertices at A(-2, 2), B(2, 5), and C(2, 0) and a first transformation of 4 units to the right and 4 units up, and a second transformation of 2 units to the left and 5 units down. What would be the location of the final B''?

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Solution

The first transformation moves point B(2, 5) 4 units to the right and 4 units up. This results in a new point B'(6, 9).

The second transformation moves point B'(6, 9) 2 units to the left and 5 units down. This results in the final point B''(4, 4).

Similar Questions

Given ABC with vertices at  A(3, 5), B(3, 6), and C (7, 1), and a first transformation of unit 1 to the right and 2 units up, and a second transformation of 6 units to the left and 4 units down, what is the new location of the  B''?

Given ΔABC with A(1, 1), B(7, -2), and C(1, -2) and if the  is rotated 90° about the (-2, -4), the new location of the B'

Given  A(3, 2), B(-4, 1), and C(6, -5) translate the  4 unit to the left and 1 unit up followed by a dilation of 3. What are the new coordinates of B''?

The coordinates of the vertices of ABC are A(-5, 1), B(-4, 5), and C(-2, 3). If the is first reflected over the y-axis and then over the x-axis, find the coordinates of A''.

Rectangle ABCD has vertices in the standard (x,y) coordinate plane at A(−4,−2), B(−4,3), C(2,3), and D(2,−2). A translation of rectangle ABCD is a second rectangle, A′B′C′D′, with vertices A′(4,−12), B′(x,y), C′(10,−7), and D′(10,−12). What are the coordinates of B′ ?Responses(3,-6)(3,-6)(4,3)(4,3)(4,-7)(4,-7)(4,-13)(4,-13)(6,-5)

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