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Given  A(3, 2), B(-4, 1), and C(6, -5) translate the  4 unit to the left and 1 unit up followed by a dilation of 3. What are the new coordinates of B''?

Question

Given  A(3, 2), B(-4, 1), and C(6, -5) translate the  4 unit to the left and 1 unit up followed by a dilation of 3. What are the new coordinates of B''?

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Solution

Step 1: Translation The first step is to translate the point B(-4, 1) 4 units to the left and 1 unit up.

To translate a point to the left, we subtract from the x-coordinate. To translate a point up, we add to the y-coordinate.

So, B' = B - 4 units left + 1 unit up = (-4 - 4, 1 + 1) = (-8, 2)

Step 2: Dilation The second step is to dilate the point B'(-8, 2) by a factor of 3.

To dilate a point, we multiply both the x-coordinate and the y-coordinate by the factor of dilation.

So, B'' = 3 * B' = 3 * (-8, 2) = (-24, 6)

Therefore, the new coordinates of B'' after the translation and dilation are (-24, 6).

This problem has been solved

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