Given ABC with vertices at A(3, 5), B(3, 6), and C (7, 1), and a first transformation of unit 1 to the right and 2 units up, and a second transformation of 6 units to the left and 4 units down, what is the new location of the B''?
Question
Given ABC with vertices at A(3, 5), B(3, 6), and C (7, 1), and a first transformation of unit 1 to the right and 2 units up, and a second transformation of 6 units to the left and 4 units down, what is the new location of the B''?
Solution
The first transformation moves point B(3, 6) 1 unit to the right and 2 units up. This results in a new point B'(4, 8).
The second transformation moves point B'(4, 8) 6 units to the left and 4 units down. This results in a new point B''(-2, 4).
So, the new location of point B'' is (-2, 4).
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