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Given ABC with vertices at  A(3, 5), B(3, 6), and C (7, 1), and a first transformation of unit 1 to the right and 2 units up, and a second transformation of 6 units to the left and 4 units down, what is the new location of the  B''?

Question

Given ABC with vertices at  A(3, 5), B(3, 6), and C (7, 1), and a first transformation of unit 1 to the right and 2 units up, and a second transformation of 6 units to the left and 4 units down, what is the new location of the  B''?

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Solution

The first transformation moves point B(3, 6) 1 unit to the right and 2 units up. This results in a new point B'(4, 8).

The second transformation moves point B'(4, 8) 6 units to the left and 4 units down. This results in a new point B''(-2, 4).

So, the new location of point B'' is (-2, 4).

Similar Questions

Given ∆ABC with vertices at A(-2, 2), B(2, 5), and C(2, 0) and a first transformation of 4 units to the right and 4 units up, and a second transformation of 2 units to the left and 5 units down. What would be the location of the final B''?

Given ABC has vertices at A(2, 2), B(4, 5), and C(6, 3), and if the is first reflected over the y-axis and then over the x-axis, find the new coordinates of the A''.

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