How many moles of neon (Ne) gas have a volume of 4.5 L and a pressure of 2.1 atm at 302 K?(The universal gas constant is 0.0821 L•atm/mol•K.)A.2.6 molB.0.38 molC.230 molD.0.086 mol
Question
How many moles of neon (Ne) gas have a volume of 4.5 L and a pressure of 2.1 atm at 302 K?(The universal gas constant is 0.0821 L•atm/mol•K.)A.2.6 molB.0.38 molC.230 molD.0.086 mol
Solution
To solve this problem, we can use the ideal gas law equation, which is PV = nRT.
Where: P = pressure V = volume n = number of moles R = universal gas constant T = temperature
We are asked to solve for n (number of moles), so we can rearrange the equation to solve for n:
n = PV/RT
Now we can plug in the given values:
P = 2.1 atm V = 4.5 L R = 0.0821 L•atm/mol•K T = 302 K
n = (2.1 atm * 4.5 L) / (0.0821 L•atm/mol•K * 302 K)
n = 9.45 atm•L / 24.7862 L•atm/mol•K
n = 0.381 mol
So, the answer is B. 0.38 mol.
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