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The 1H NMR spectrum of a compound with the molecular formula C7H15Cl exhibits signals with relative integration 9:3:2:1. Propose a structure for this compound.Select answer from the options below3-chloro-2,4-dimethylpentane3-chloro-2,2-dimethylpentane 4-chloroheptane 2-chloro-2,3,3-trimethylbutane Save for LaterSubmit Answer

Question

The 1H NMR spectrum of a compound with the molecular formula C7H15Cl exhibits signals with relative integration 9:3:2:1. Propose a structure for this compound.Select answer from the options below3-chloro-2,4-dimethylpentane3-chloro-2,2-dimethylpentane 4-chloroheptane 2-chloro-2,3,3-trimethylbutane Save for LaterSubmit Answer

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Solution

The molecular formula C7H15Cl indicates that the compound contains 7 carbons. The 1H NMR spectrum shows signals with relative integration 9:3:2:1. This suggests that the compound has four different types of protons.

The integration of the signals suggests that there are 9 protons of one type, 3 protons of another type, 2 protons of a third type, and 1 proton of a fourth type.

Given the options, the compound that fits this description is 3-chloro-2,2-dimethylpentane.

This compound has a methyl group (3 protons) on the second carbon, another methyl group (3 protons) on the second carbon, a methylene group (2 protons) on the third carbon, and a methyl group (1 proton) on the third carbon. The remaining 9 protons come from the 3 methylene groups (each with 2 protons) and the terminal methyl group (3 protons) on the pentane chain.

Therefore, the correct answer is 3-chloro-2,2-dimethylpentane.

This problem has been solved

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