Which of the following molecules will produce a 1H-NMR spectrum with a peak area ratio of 3 : 1?I CH3CH2CH3 II CH3CHCl2III CH3OH
Question
Which of the following molecules will produce a 1H-NMR spectrum with a peak area ratio of 3 : 1?I CH3CH2CH3 II CH3CHCl2III CH3OH
Solution
The 1H-NMR spectrum peak area ratio is determined by the number of equivalent protons in the molecule. The ratio 3:1 means there are two types of protons in the molecule, one type three times as abundant as the other.
I. CH3CH2CH3 (Propane) - This molecule has two types of protons, but in a ratio of 6:2 (3 CH3 protons and 2 CH2 protons), not 3:1.
II. CH3CHCl2 (1,1-dichloroethane) - This molecule has two types of protons, but in a ratio of 3:2 (3 CH3 protons and 2 CH protons), not 3:1.
III. CH3OH (Methanol) - This molecule has two types of protons, in a ratio of 3:1 (3 CH3 protons and 1 OH proton).
So, the molecule that will produce a 1H-NMR spectrum with a peak area ratio of 3:1 is Methanol (CH3OH).
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