The digit in unit‘s place of the number (1570)2 + (1571)2 +(1572)2 + (1573)2 ?Options4123

Sure, let's solve this step by step:

1. First, we need to find the unit's place digit of each individual number when squared.

2. The unit's place digit of (1570)^2, (1571)^2, (1572)^2, and (1573)^2 are 0, 1, 4, and 9 respectively. This is because the unit's place digit of a number squared is determined by the unit's place digit of the original number. For example, any number ending in 0 when squared will end in 0, any number ending in 1 when squared will end in 1, any number ending in 2 when squared will end in 4, and any number ending in 3 when squared will end in 9.

3. Now, we add these unit's place digits together: 0 + 1 + 4 + 9 = 14.

4. The unit's place digit of the sum (14) is 4.

So, the digit in the unit's place of the number (1570)^2 + (1571)^2 +(1572)^2 + (1573)^2 is 4.