The difference between the digits of a two-digit number is 4 and the digit in the unit’s place is one-third of the digit in the tenth’s place. what is the two -digit number?Options2693cannot be determined6231

The problem states that the difference between the digits of a two-digit number is 4 and the digit in the unit’s place is one-third of the digit in the tenth’s place.

Let's denote the digit in the tenth's place as x and the digit in the unit's place as y.

From the problem, we have two equations:

1. x - y = 4 (since the difference between the digits is 4)
2. y = x/3 (since the digit in the unit’s place is one-third of the digit in the tenth’s place)

We can solve these equations simultaneously. Substituting the second equation into the first, we get:

x - x/3 = 4 2x/3 = 4 x = 6

Substituting x = 6 into the second equation, we get:

y = 6/3 y = 2

So, the two-digit number is 62. Therefore, the correct option is 6231.

The problem states that the difference between the digits of a two-digit number is 4 and the digit in the unit’s place is one-third of the digit in the tenth’s place.

Let's denote the digit in the tenth's place as x and the digit in the unit's place as y.

From the problem, we have two equations:

1. x - y = 4 (since the difference between the digits is 4)
2. y = x/3 (since the digit in the unit’s place is one-third of the digit in the tenth’s place)

We can solve these equations simultaneously to find the values of x and y.

Substitute equation 2) into equation 1):

x - x/3 = 4 Multiply all terms by 3 to clear the fraction: 3x - x = 12 2x = 12 x = 6

Substitute x = 6 into equation 2) to find y: y = 6/3 y = 2

So, the two-digit number is 62.

Therefore, the correct option is 62.